3z/7-4z=1

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Solution for 3z/7-4z=1 equation:



3z/7-4z=1
We move all terms to the left:
3z/7-4z-(1)=0
We add all the numbers together, and all the variables
-4z+3z/7-1=0
We multiply all the terms by the denominator
-4z*7+3z-1*7=0
We add all the numbers together, and all the variables
3z-4z*7-7=0
Wy multiply elements
3z-28z-7=0
We add all the numbers together, and all the variables
-25z-7=0
We move all terms containing z to the left, all other terms to the right
-25z=7
z=7/-25
z=-7/25

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