(3x+2)(2x-1)=35

Solution for (3x+2)(2x-1)=35 equation:

(3x+2)(2x-1)=35

We move all terms to the left:

(3x+2)(2x-1)-(35)=0

We multiply parentheses ..

(+6x^2-3x+4x-2)-35=0

We get rid of parentheses

6x^2-3x+4x-2-35=0

We add all the numbers together, and all the variables

6x^2+x-37=0

a = 6; b = 1; c = -37;
Δ = b2-4ac
Δ = 12-4·6·(-37)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{889}}{2*6}=\frac{-1-\sqrt{889}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{889}}{2*6}=\frac{-1+\sqrt{889}}{12}
$