3z+7=3(z+4)-5

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Solution for 3z+7=3(z+4)-5 equation: 



3z+7=3(z+4)-5

We move all terms to the left:

3z+7-(3(z+4)-5)=0



We calculate terms in parentheses: -(3(z+4)-5), so:

3(z+4)-5

We multiply parentheses

3z+12-5

We add all the numbers together, and all the variables

3z+7

Back to the equation:

-(3z+7)



We get rid of parentheses

3z-3z-7+7=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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