15=(7/5)(4x+15)

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Solution for 15=(7/5)(4x+15) equation: 



15=(7/5)(4x+15)

We move all terms to the left:

15-((7/5)(4x+15))=0



Domain of the equation: 5)(4x+15))!=0

x∈R



We add all the numbers together, and all the variables

-((+7/5)(4x+15))+15=0

We multiply parentheses ..

-((+28x^2+7/5*15))+15=0

We multiply all the terms by the denominator


-((+28x^2+7+15*5*15))=0



We calculate terms in parentheses: -((+28x^2+7+15*5*15)), so:

(+28x^2+7+15*5*15)

We get rid of parentheses

28x^2+7+15*5*15

We add all the numbers together, and all the variables

28x^2+1132

Back to the equation:

-(28x^2+1132)



We get rid of parentheses

-28x^2-1132=0

a = -28; b = 0; c = -1132;
Δ = b2-4ac
Δ = 02-4·(-28)·(-1132)
Δ = -126784
Delta is less than zero, so there is no solution for the equation

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