3z+47+4z=14z-9

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Solution for 3z+47+4z=14z-9 equation: 



3z+47+4z=14z-9

We move all terms to the left:

3z+47+4z-(14z-9)=0

We add all the numbers together, and all the variables

7z-(14z-9)+47=0

We get rid of parentheses

7z-14z+9+47=0

We add all the numbers together, and all the variables

-7z+56=0

We move all terms containing z to the left, all other terms to the right

-7z=-56

z=-56/-7

z=+8

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