4(y+5)=3(y-2)-2(y+2)

Solution for 4(y+5)=3(y-2)-2(y+2) equation:

4(y+5)=3(y-2)-2(y+2)

We move all terms to the left:

4(y+5)-(3(y-2)-2(y+2))=0

We multiply parentheses

4y-(3(y-2)-2(y+2))+20=0


We calculate terms in parentheses: -(3(y-2)-2(y+2)), so:

3(y-2)-2(y+2)

We multiply parentheses

3y-2y-6-4

We add all the numbers together, and all the variables

y-10

Back to the equation:

-(y-10)


We get rid of parentheses

4y-y+10+20=0

We add all the numbers together, and all the variables

3y+30=0

We move all terms containing y to the left, all other terms to the right

3y=-30

y=-30/3

y=-10