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3y=8-2(y-1)
We move all terms to the left:
3y-(8-2(y-1))=0
We calculate terms in parentheses: -(8-2(y-1)), so:We get rid of parentheses
8-2(y-1)
determiningTheFunctionDomain -2(y-1)+8
We multiply parentheses
-2y+2+8
We add all the numbers together, and all the variables
-2y+10
Back to the equation:
-(-2y+10)
3y+2y-10=0
We add all the numbers together, and all the variables
5y-10=0
We move all terms containing y to the left, all other terms to the right
5y=10
y=10/5
y=2
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