-2(7u-6)+8u=2+2(6u-2)

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Solution for -2(7u-6)+8u=2+2(6u-2) equation: 



-2(7u-6)+8u=2+2(6u-2)

We move all terms to the left:

-2(7u-6)+8u-(2+2(6u-2))=0

We add all the numbers together, and all the variables

8u-2(7u-6)-(2+2(6u-2))=0

We multiply parentheses

8u-14u-(2+2(6u-2))+12=0



We calculate terms in parentheses: -(2+2(6u-2)), so:

2+2(6u-2)

determiningTheFunctionDomain
2(6u-2)+2

We multiply parentheses

12u-4+2

We add all the numbers together, and all the variables

12u-2

Back to the equation:

-(12u-2)



We add all the numbers together, and all the variables

-6u-(12u-2)+12=0

We get rid of parentheses

-6u-12u+2+12=0

We add all the numbers together, and all the variables

-18u+14=0

We move all terms containing u to the left, all other terms to the right

-18u=-14

u=-14/-18

u=7/9

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