3y2=2601

Solution for 3y2=2601 equation:

3y^2=2601

We move all terms to the left:

3y^2-(2601)=0

a = 3; b = 0; c = -2601;
Δ = b2-4ac
Δ = 02-4·3·(-2601)
Δ = 31212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31212}=\sqrt{10404*3}=\sqrt{10404}*\sqrt{3}=102\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-102\sqrt{3}}{2*3}=\frac{0-102\sqrt{3}}{6}
=-\frac{102\sqrt{3}}{6}
=-17\sqrt{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+102\sqrt{3}}{2*3}=\frac{0+102\sqrt{3}}{6}
=\frac{102\sqrt{3}}{6}
=17\sqrt{3}
$