2(n-1)+n=5(2n+3)-2(n+3)

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Solution for 2(n-1)+n=5(2n+3)-2(n+3) equation: 



2(n-1)+n=5(2n+3)-2(n+3)

We move all terms to the left:

2(n-1)+n-(5(2n+3)-2(n+3))=0

We add all the numbers together, and all the variables

n+2(n-1)-(5(2n+3)-2(n+3))=0

We multiply parentheses

n+2n-(5(2n+3)-2(n+3))-2=0



We calculate terms in parentheses: -(5(2n+3)-2(n+3)), so:

5(2n+3)-2(n+3)

We multiply parentheses

10n-2n+15-6

We add all the numbers together, and all the variables

8n+9

Back to the equation:

-(8n+9)



We add all the numbers together, and all the variables

3n-(8n+9)-2=0

We get rid of parentheses

3n-8n-9-2=0

We add all the numbers together, and all the variables

-5n-11=0

We move all terms containing n to the left, all other terms to the right

-5n=11

n=11/-5

n=-2+1/5

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