3y-7=5(2y-3+4)

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Solution for 3y-7=5(2y-3+4) equation: 



3y-7=5(2y-3+4)

We move all terms to the left:

3y-7-(5(2y-3+4))=0

We add all the numbers together, and all the variables

3y-(5(2y+1))-7=0



We calculate terms in parentheses: -(5(2y+1)), so:

5(2y+1)

We multiply parentheses

10y+5

Back to the equation:

-(10y+5)



We get rid of parentheses

3y-10y-5-7=0

We add all the numbers together, and all the variables

-7y-12=0

We move all terms containing y to the left, all other terms to the right

-7y=12

y=12/-7

y=-1+5/7

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