3y-7+3(2y+2)=-6(y+1)

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Solution for 3y-7+3(2y+2)=-6(y+1) equation: 



3y-7+3(2y+2)=-6(y+1)

We move all terms to the left:

3y-7+3(2y+2)-(-6(y+1))=0

We multiply parentheses

3y+6y-(-6(y+1))+6-7=0



We calculate terms in parentheses: -(-6(y+1)), so:

-6(y+1)

We multiply parentheses

-6y-6

Back to the equation:

-(-6y-6)



We add all the numbers together, and all the variables

9y-(-6y-6)-1=0

We get rid of parentheses

9y+6y+6-1=0

We add all the numbers together, and all the variables

15y+5=0

We move all terms containing y to the left, all other terms to the right

15y=-5

y=-5/15

y=-1/3

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