-4(3v-4)+2v=4(v+6)

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Solution for -4(3v-4)+2v=4(v+6) equation: 



-4(3v-4)+2v=4(v+6)

We move all terms to the left:

-4(3v-4)+2v-(4(v+6))=0

We add all the numbers together, and all the variables

2v-4(3v-4)-(4(v+6))=0

We multiply parentheses

2v-12v-(4(v+6))+16=0



We calculate terms in parentheses: -(4(v+6)), so:

4(v+6)

We multiply parentheses

4v+24

Back to the equation:

-(4v+24)



We add all the numbers together, and all the variables

-10v-(4v+24)+16=0

We get rid of parentheses

-10v-4v-24+16=0

We add all the numbers together, and all the variables

-14v-8=0

We move all terms containing v to the left, all other terms to the right

-14v=8

v=8/-14

v=-4/7

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