3y-4(y+2)=5

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Solution for 3y-4(y+2)=5 equation: 



3y-4(y+2)=5

We move all terms to the left:

3y-4(y+2)-(5)=0

We multiply parentheses

3y-4y-8-5=0

We add all the numbers together, and all the variables

-1y-13=0

We move all terms containing y to the left, all other terms to the right

-y=13

y=13/-1

y=-13

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