6(1x+2)=78

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Solution for 6(1x+2)=78 equation: 



6(1x+2)=78

We move all terms to the left:

6(1x+2)-(78)=0

We add all the numbers together, and all the variables

6(x+2)-78=0

We multiply parentheses

6x+12-78=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11

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