3y-38=8(y-1)

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Solution for 3y-38=8(y-1) equation: 



3y-38=8(y-1)

We move all terms to the left:

3y-38-(8(y-1))=0



We calculate terms in parentheses: -(8(y-1)), so:

8(y-1)

We multiply parentheses

8y-8

Back to the equation:

-(8y-8)



We get rid of parentheses

3y-8y+8-38=0

We add all the numbers together, and all the variables

-5y-30=0

We move all terms containing y to the left, all other terms to the right

-5y=30

y=30/-5

y=-6

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