1/3x(6-5)-x=1/3-2(x+1)

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Solution for 1/3x(6-5)-x=1/3-2(x+1) equation: 



1/3x(6-5)-x=1/3-2(x+1)

We move all terms to the left:

1/3x(6-5)-x-(1/3-2(x+1))=0



Domain of the equation: 3x(6-5)!=0

x∈R





Domain of the equation: 3-2(x+1))!=0

We move all terms containing x to the left, all other terms to the right

-2(x+1))!=-3

x∈R



We add all the numbers together, and all the variables

1/3x1-x-(1/3-2(x+1))=0

We add all the numbers together, and all the variables

-1x+1/3x1-(1/3-2(x+1))=0

We calculate fractions


-1x+(-2(x+1))+1*3)/7x+(-(1*3x1)/7x=0



We calculate terms in parentheses: +(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

+(-2x-2)



We add all the numbers together, and all the variables

-1x+(-2x-2)+1*3)/7x+(-(+1*3x1)/7x=0

We get rid of parentheses

-1x-2x+1*3)/7x+(-(+1*3x1)/7x-2=0

We calculate fractions


21x^2/(7x+(*7x)+(-21x^2)/(7x+(*7x)-1x-2x-2=0

We can not solve this equation

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