3y-2(y-2)+4=7

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Solution for 3y-2(y-2)+4=7 equation: 



3y-2(y-2)+4=7

We move all terms to the left:

3y-2(y-2)+4-(7)=0

We add all the numbers together, and all the variables

3y-2(y-2)-3=0

We multiply parentheses

3y-2y+4-3=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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