-4(3y-4)-y=-2(y-3)

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Solution for -4(3y-4)-y=-2(y-3) equation: 



-4(3y-4)-y=-2(y-3)

We move all terms to the left:

-4(3y-4)-y-(-2(y-3))=0

We add all the numbers together, and all the variables

-1y-4(3y-4)-(-2(y-3))=0

We multiply parentheses

-1y-12y-(-2(y-3))+16=0



We calculate terms in parentheses: -(-2(y-3)), so:

-2(y-3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We add all the numbers together, and all the variables

-13y-(-2y+6)+16=0

We get rid of parentheses

-13y+2y-6+16=0

We add all the numbers together, and all the variables

-11y+10=0

We move all terms containing y to the left, all other terms to the right

-11y=-10

y=-10/-11

y=10/11

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