3y+8-2(-7y-1)=3(y-2)

Solution for 3y+8-2(-7y-1)=3(y-2) equation:

3y+8-2(-7y-1)=3(y-2)

We move all terms to the left:

3y+8-2(-7y-1)-(3(y-2))=0

We multiply parentheses

3y+14y-(3(y-2))+2+8=0


We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)


We add all the numbers together, and all the variables

17y-(3y-6)+10=0

We get rid of parentheses

17y-3y+6+10=0

We add all the numbers together, and all the variables

14y+16=0

We move all terms containing y to the left, all other terms to the right

14y=-16

y=-16/14

y=-1+1/7