(10z+45)=3(6z+7)

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Solution for (10z+45)=3(6z+7) equation: 



(10z+45)=3(6z+7)

We move all terms to the left:

(10z+45)-(3(6z+7))=0

We get rid of parentheses

10z-(3(6z+7))+45=0



We calculate terms in parentheses: -(3(6z+7)), so:

3(6z+7)

We multiply parentheses

18z+21

Back to the equation:

-(18z+21)



We get rid of parentheses

10z-18z-21+45=0

We add all the numbers together, and all the variables

-8z+24=0

We move all terms containing z to the left, all other terms to the right

-8z=-24

z=-24/-8

z=+3

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