2(y-3)+14y=8y-20

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Solution for 2(y-3)+14y=8y-20 equation: 



2(y-3)+14y=8y-20

We move all terms to the left:

2(y-3)+14y-(8y-20)=0

We add all the numbers together, and all the variables

14y+2(y-3)-(8y-20)=0

We multiply parentheses

14y+2y-(8y-20)-6=0

We get rid of parentheses

14y+2y-8y+20-6=0

We add all the numbers together, and all the variables

8y+14=0

We move all terms containing y to the left, all other terms to the right

8y=-14

y=-14/8

y=-1+3/4

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