3y+7=8(4y-10)

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Solution for 3y+7=8(4y-10) equation: 



3y+7=8(4y-10)

We move all terms to the left:

3y+7-(8(4y-10))=0



We calculate terms in parentheses: -(8(4y-10)), so:

8(4y-10)

We multiply parentheses

32y-80

Back to the equation:

-(32y-80)



We get rid of parentheses

3y-32y+80+7=0

We add all the numbers together, and all the variables

-29y+87=0

We move all terms containing y to the left, all other terms to the right

-29y=-87

y=-87/-29

y=+3

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