3y+24=(10y-40)+8

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Solution for 3y+24=(10y-40)+8 equation:



3y+24=(10y-40)+8
We move all terms to the left:
3y+24-((10y-40)+8)=0
We calculate terms in parentheses: -((10y-40)+8), so:
(10y-40)+8
We get rid of parentheses
10y-40+8
We add all the numbers together, and all the variables
10y-32
Back to the equation:
-(10y-32)
We get rid of parentheses
3y-10y+32+24=0
We add all the numbers together, and all the variables
-7y+56=0
We move all terms containing y to the left, all other terms to the right
-7y=-56
y=-56/-7
y=+8

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