3y+1=6y-3+4y

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Solution for 3y+1=6y-3+4y equation: 



3y+1=6y-3+4y

We move all terms to the left:

3y+1-(6y-3+4y)=0

We add all the numbers together, and all the variables

3y-(10y-3)+1=0

We get rid of parentheses

3y-10y+3+1=0

We add all the numbers together, and all the variables

-7y+4=0

We move all terms containing y to the left, all other terms to the right

-7y=-4

y=-4/-7

y=4/7

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