2x+45=-7(3+10x)+6x

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Solution for 2x+45=-7(3+10x)+6x equation: 



2x+45=-7(3+10x)+6x

We move all terms to the left:

2x+45-(-7(3+10x)+6x)=0

We add all the numbers together, and all the variables

2x-(-7(10x+3)+6x)+45=0



We calculate terms in parentheses: -(-7(10x+3)+6x), so:

-7(10x+3)+6x

We add all the numbers together, and all the variables

6x-7(10x+3)

We multiply parentheses

6x-70x-21

We add all the numbers together, and all the variables

-64x-21

Back to the equation:

-(-64x-21)



We get rid of parentheses

2x+64x+21+45=0

We add all the numbers together, and all the variables

66x+66=0

We move all terms containing x to the left, all other terms to the right

66x=-66

x=-66/66

x=-1

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