3y(y+11)=0

Solution for 3y(y+11)=0 equation:

3y(y+11)=0

We multiply parentheses

3y^2+33y=0

a = 3; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·3·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*3}=\frac{-66}{6}
=-11
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*3}=\frac{0}{6}
=0
$