5(y+7)-3(2y+4)=2-4(y-3)

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Solution for 5(y+7)-3(2y+4)=2-4(y-3) equation: 



5(y+7)-3(2y+4)=2-4(y-3)

We move all terms to the left:

5(y+7)-3(2y+4)-(2-4(y-3))=0

We multiply parentheses

5y-6y-(2-4(y-3))+35-12=0



We calculate terms in parentheses: -(2-4(y-3)), so:

2-4(y-3)

determiningTheFunctionDomain
-4(y-3)+2

We multiply parentheses

-4y+12+2

We add all the numbers together, and all the variables

-4y+14

Back to the equation:

-(-4y+14)



We add all the numbers together, and all the variables

-1y-(-4y+14)+23=0

We get rid of parentheses

-1y+4y-14+23=0

We add all the numbers together, and all the variables

3y+9=0

We move all terms containing y to the left, all other terms to the right

3y=-9

y=-9/3

y=-3

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