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3x=4-8/16x
We move all terms to the left:
3x-(4-8/16x)=0
Domain of the equation: 16x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(-8/16x+4)=0
We get rid of parentheses
3x+8/16x-4=0
We multiply all the terms by the denominator
3x*16x-4*16x+8=0
Wy multiply elements
48x^2-64x+8=0
a = 48; b = -64; c = +8;
Δ = b2-4ac
Δ = -642-4·48·8
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16\sqrt{10}}{2*48}=\frac{64-16\sqrt{10}}{96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16\sqrt{10}}{2*48}=\frac{64+16\sqrt{10}}{96} $
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