42=1/2+(2x+8)+(x+3)

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Solution for 42=1/2+(2x+8)+(x+3) equation: 



42=1/2+(2x+8)+(x+3)

We move all terms to the left:

42-(1/2+(2x+8)+(x+3))=0



Domain of the equation: 2+(2x+8)+(x+3))!=0

We move all terms containing x to the left, all other terms to the right

(2x+8)+(x+3))!=-2

x∈R



We multiply all the terms by the denominator


-(1+42*2+(2x+8)+(x+3))=0



We calculate terms in parentheses: -(1+42*2+(2x+8)+(x+3)), so:

1+42*2+(2x+8)+(x+3)

determiningTheFunctionDomain
(2x+8)+(x+3)+1+42*2

We add all the numbers together, and all the variables

(2x+8)+(x+3)+85

We get rid of parentheses

2x+x+8+3+85

We add all the numbers together, and all the variables

3x+96

Back to the equation:

-(3x+96)



We get rid of parentheses

-3x-96=0

We move all terms containing x to the left, all other terms to the right

-3x=96

x=96/-3

x=-32

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