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3x^2=46
We move all terms to the left:
3x^2-(46)=0
a = 3; b = 0; c = -46;
Δ = b2-4ac
Δ = 02-4·3·(-46)
Δ = 552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{552}=\sqrt{4*138}=\sqrt{4}*\sqrt{138}=2\sqrt{138}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{138}}{2*3}=\frac{0-2\sqrt{138}}{6} =-\frac{2\sqrt{138}}{6} =-\frac{\sqrt{138}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{138}}{2*3}=\frac{0+2\sqrt{138}}{6} =\frac{2\sqrt{138}}{6} =\frac{\sqrt{138}}{3} $
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