15=3(2x-1)2x

Solution for 15=3(2x-1)2x equation:

15=3(2x-1)2x

We move all terms to the left:

15-(3(2x-1)2x)=0


We calculate terms in parentheses: -(3(2x-1)2x), so:

3(2x-1)2x

We multiply parentheses

12x^2-6x

Back to the equation:

-(12x^2-6x)


We get rid of parentheses

-12x^2+6x+15=0

a = -12; b = 6; c = +15;
Δ = b2-4ac
Δ = 62-4·(-12)·15
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{21}}{2*-12}=\frac{-6-6\sqrt{21}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{21}}{2*-12}=\frac{-6+6\sqrt{21}}{-24}
$