3x2=-7x+136

Solution for 3x2=-7x+136 equation:

3x^2=-7x+136

We move all terms to the left:

3x^2-(-7x+136)=0

We get rid of parentheses

3x^2+7x-136=0

a = 3; b = 7; c = -136;
Δ = b2-4ac
Δ = 72-4·3·(-136)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-41}{2*3}=\frac{-48}{6}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+41}{2*3}=\frac{34}{6}
=5+2/3
$