3(x+1)=(21+3x)/20

Solution for 3(x+1)=(21+3x)/20 equation:

3(x+1)=(21+3x)/20

We move all terms to the left:

3(x+1)-((21+3x)/20)=0

We add all the numbers together, and all the variables

3(x+1)-((3x+21)/20)=0

We multiply parentheses

3x-((3x+21)/20)+3=0

We multiply all the terms by the denominator


3x*20)-((3x+21)+3*20)=0

We add all the numbers together, and all the variables

3x*20)-((3x+21)=0

Wy multiply elements

60x^2=0

a = 60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·60·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{120}=0$