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3x^2-x-127=0
We add all the numbers together, and all the variables
3x^2-1x-127=0
a = 3; b = -1; c = -127;
Δ = b2-4ac
Δ = -12-4·3·(-127)
Δ = 1525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1525}=\sqrt{25*61}=\sqrt{25}*\sqrt{61}=5\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5\sqrt{61}}{2*3}=\frac{1-5\sqrt{61}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5\sqrt{61}}{2*3}=\frac{1+5\sqrt{61}}{6} $
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