If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-5x-10=x
We move all terms to the left:
3x^2-5x-10-(x)=0
We add all the numbers together, and all the variables
3x^2-6x-10=0
a = 3; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·3·(-10)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{39}}{2*3}=\frac{6-2\sqrt{39}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{39}}{2*3}=\frac{6+2\sqrt{39}}{6} $
| x/2=-4 | | t=3.25 | | 6-(-2)^2=x | | 4(x-5)=12•x•x | | 8c÷2c=2 | | 3x-4=-37 | | y/3=72 | | P=3.7*10^-4k | | -(18=4x)=8 | | (3p+3)=(4p+3) | | 4(x+3)=2(2x+9)-6 | | 300+0.14x=200+.025x.011x=100 | | 83/5=-4z | | 57=x-23 | | f(2)=6-2*2√2*2 | | .20x+0.80(20-x)=(0.20)(35) | | .30x+0.60(15-x)=(0.30)(40) | | -38d-57=-19+76 | | f(2)=6-2*2/2*2 | | 5(-1/5+9/5)=x-1 | | x(2x-2)+x(2x-2)=(4x+9)(x-4) | | 7x-(-3)=1 | | 22-4x=12x=+126 | | 5t=135 | | 0.22y-0.6=0.12y+3 | | -3y-9=12 | | 5t+9=3t-3 | | 0x+1=3 | | -5-3x=-20 | | (2x+3)(x-2)=22 | | 8.8t-6.2=33+3.2t | | 18/3=x/63 |