x(2x-2)+x(2x-2)=(4x+9)(x-4)

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Solution for x(2x-2)+x(2x-2)=(4x+9)(x-4) equation: 



x(2x-2)+x(2x-2)=(4x+9)(x-4)

We move all terms to the left:

x(2x-2)+x(2x-2)-((4x+9)(x-4))=0

We multiply parentheses

2x^2+2x^2-2x-2x-((4x+9)(x-4))=0

We multiply parentheses ..

2x^2+2x^2-((+4x^2-16x+9x-36))-2x-2x=0



We calculate terms in parentheses: -((+4x^2-16x+9x-36)), so:

(+4x^2-16x+9x-36)

We get rid of parentheses

4x^2-16x+9x-36

We add all the numbers together, and all the variables

4x^2-7x-36

Back to the equation:

-(4x^2-7x-36)



We add all the numbers together, and all the variables

4x^2-4x-(4x^2-7x-36)=0

We get rid of parentheses

4x^2-4x^2-4x+7x+36=0

We add all the numbers together, and all the variables

3x+36=0

We move all terms containing x to the left, all other terms to the right

3x=-36

x=-36/3

x=-12

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