3x2-4x-10=8

Solution for 3x2-4x-10=8 equation:

3x^2-4x-10=8

We move all terms to the left:

3x^2-4x-10-(8)=0

We add all the numbers together, and all the variables

3x^2-4x-18=0

a = 3; b = -4; c = -18;
Δ = b2-4ac
Δ = -42-4·3·(-18)
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{58}}{2*3}=\frac{4-2\sqrt{58}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{58}}{2*3}=\frac{4+2\sqrt{58}}{6}
$