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1/5(x+3)=2x
We move all terms to the left:
1/5(x+3)-(2x)=0
Domain of the equation: 5(x+3)!=0We add all the numbers together, and all the variables
x∈R
-2x+1/5(x+3)=0
We multiply all the terms by the denominator
-2x*5(x+3)+1=0
Wy multiply elements
-10x^2(x+1=0
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