0.006(3-k)+0.08(k-7)=1

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Solution for 0.006(3-k)+0.08(k-7)=1 equation: 



0.006(3-k)+0.08(k-7)=1

We move all terms to the left:

0.006(3-k)+0.08(k-7)-(1)=0

We add all the numbers together, and all the variables

0.006(-1k+3)+0.08(k-7)-1=0

We multiply parentheses

-0.006k+0.08k+0.018-0.56-1=0

We add all the numbers together, and all the variables

0.074k-1.542=0

We move all terms containing k to the left, all other terms to the right

0.074k=1.542

k=1.542/0.074

k=20+0.062/0.074

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