3x2-259x=0

Solution for 3x2-259x=0 equation:

3x^2-259x=0

a = 3; b = -259; c = 0;
Δ = b2-4ac
Δ = -2592-4·3·0
Δ = 67081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67081}=259$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-259)-259}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-259)+259}{2*3}=\frac{518}{6}
=86+1/3
$