6(r-1)+8r=2(1+6r)

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Solution for 6(r-1)+8r=2(1+6r) equation: 



6(r-1)+8r=2(1+6r)

We move all terms to the left:

6(r-1)+8r-(2(1+6r))=0

We add all the numbers together, and all the variables

6(r-1)+8r-(2(6r+1))=0

We add all the numbers together, and all the variables

8r+6(r-1)-(2(6r+1))=0

We multiply parentheses

8r+6r-(2(6r+1))-6=0



We calculate terms in parentheses: -(2(6r+1)), so:

2(6r+1)

We multiply parentheses

12r+2

Back to the equation:

-(12r+2)



We add all the numbers together, and all the variables

14r-(12r+2)-6=0

We get rid of parentheses

14r-12r-2-6=0

We add all the numbers together, and all the variables

2r-8=0

We move all terms containing r to the left, all other terms to the right

2r=8

r=8/2

r=4

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