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3x^2-17x+4=0
a = 3; b = -17; c = +4;
Δ = b2-4ac
Δ = -172-4·3·4
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{241}}{2*3}=\frac{17-\sqrt{241}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{241}}{2*3}=\frac{17+\sqrt{241}}{6} $
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