3x2+x-56=14

Solution for 3x2+x-56=14 equation:

3x^2+x-56=14

We move all terms to the left:

3x^2+x-56-(14)=0

We add all the numbers together, and all the variables

3x^2+x-70=0

a = 3; b = 1; c = -70;
Δ = b2-4ac
Δ = 12-4·3·(-70)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-29}{2*3}=\frac{-30}{6}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+29}{2*3}=\frac{28}{6}
=4+2/3
$