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4x^2-36=714
We move all terms to the left:
4x^2-36-(714)=0
We add all the numbers together, and all the variables
4x^2-750=0
a = 4; b = 0; c = -750;
Δ = b2-4ac
Δ = 02-4·4·(-750)
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{30}}{2*4}=\frac{0-20\sqrt{30}}{8} =-\frac{20\sqrt{30}}{8} =-\frac{5\sqrt{30}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{30}}{2*4}=\frac{0+20\sqrt{30}}{8} =\frac{20\sqrt{30}}{8} =\frac{5\sqrt{30}}{2} $
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