3x2+84x=0

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Solution for 3x2+84x=0 equation:



3x^2+84x=0
a = 3; b = 84; c = 0;
Δ = b2-4ac
Δ = 842-4·3·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-84}{2*3}=\frac{-168}{6} =-28 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+84}{2*3}=\frac{0}{6} =0 $

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