9(k-3)=(k-2)

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Solution for 9(k-3)=(k-2) equation: 



9(k-3)=(k-2)

We move all terms to the left:

9(k-3)-((k-2))=0

We multiply parentheses

9k-((k-2))-27=0



We calculate terms in parentheses: -((k-2)), so:

(k-2)

We get rid of parentheses

k-2

Back to the equation:

-(k-2)



We get rid of parentheses

9k-k+2-27=0

We add all the numbers together, and all the variables

8k-25=0

We move all terms containing k to the left, all other terms to the right

8k=25

k=25/8

k=3+1/8

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