3x/24-2-x/10=5+x/40-1/15

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Solution for 3x/24-2-x/10=5+x/40-1/15 equation: 


x in (-oo:+oo)

(3*x)/24-(x/10)-2 = x/40-(1/15)+5 // - x/40-(1/15)+5

(3*x)/24-(x/10)-(x/40)+1/15-5-2 = 0

-104/15 = 0

x belongs to the empty set

x belongs to the empty set

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