(29/x+3)+2x=10

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Solution for (29/x+3)+2x=10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+29/x+3 = 10 // - 10

2*x+29/x-10+3 = 0

2*x^1+29*x^-1-7*x^0 = 0

(2*x^2-7*x^1+29*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-7*x^1+29*x^0) = 0

x^1

2*x^2-7*x+29 = 0

2*x^2-7*x+29 = 0

DELTA = (-7)^2-(2*4*29)

DELTA = -183

DELTA < 0

x in { } 

x belongs to the empty set

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