3x/(3x+7)-(3x+7)/3x=14

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Solution for 3x/(3x+7)-(3x+7)/3x=14 equation:



3x/(3x+7)-(3x+7)/3x=14
We move all terms to the left:
3x/(3x+7)-(3x+7)/3x-(14)=0
Domain of the equation: (3x+7)!=0
We move all terms containing x to the left, all other terms to the right
3x!=-7
x!=-7/3
x!=-2+1/3
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We calculate fractions
9x^2/(9x^2+21x)+(-(3x+7)*(3x+7))/(9x^2+21x)-14=0
We calculate terms in parentheses: +(-(3x+7)*(3x+7))/(9x^2+21x), so:
-(3x+7)*(3x+7))/(9x^2+21x
We add all the numbers together, and all the variables
21x-(3x+7)*(3x+7))/(9x^2
We multiply all the terms by the denominator
21x*(9x^2-(3x+7)*(3x+7))
Back to the equation:
+(21x*(9x^2-(3x+7)*(3x+7)))
We multiply all the terms by the denominator
9x^2+((21x*(9x^2-(3x+7)*(3x+7))))*(9x^2+21x)-14*(9x^2+21x)=0
We calculate terms in parentheses: +((21x*(9x^2-(3x+7)*(3x+7))))*(9x^2+21x), so:
(21x*(9x^2-(3x+7)*(3x+7))))*(9x^2+21x
We add all the numbers together, and all the variables
21x+(21x*(9x^2-(3x+7)*(3x+7))))*(9x^2
Back to the equation:
+(21x+(21x*(9x^2-(3x+7)*(3x+7))))*(9x^2)
We multiply parentheses
9x^2-126x^2+(21x+(21x*(9x^2-(3x+7)*(3x+7))))*9x^2-294x=0
We add all the numbers together, and all the variables
-117x^2-294x+(21x+(21x*(9x^2-(3x+7)*(3x+7))))*9x^2=0

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